Python 发送邮件，邮件可以正常接收，但收件人栏显示异常

資深大佬 : Kvip 5

如题，使用 python 编写了个发送邮件的 Demo 。邮件发送后，用 Foxmail 能够正常收的到。

但是收件人一栏显示的收件邮箱很奇怪，如下图，一整个收件邮箱被按字符拆分为好多个小邮箱，小邮箱的那域名我也没见过。

原本收件邮箱应该显示是 [email protected]

不知道有大佬遇到过这种情况没，请教下

Python 发送邮件，邮件可以正常接收，但收件人栏显示异常

下面是源码（看着没毛病）：

# 编译日期：2019-10-14 15:01:36 # coding=utf-8  import os from email.mime.text import MIMEText from email.header import Header from email.mime.multipart import MIMEMultipart from email.mime.application import MIMEApplication  # 发送邮件（附件） # email_user: 发件人 # email_pass: 密码 # receivers：收件人列表，例：['[email protected]','[email protected]'] # filepath: 文件地址 如：r'D:分行查询支行卷别库存 Excel作文.xlsx' def sendEmail(email_user, email_pass, receivers, filepath):     mail_host = '10.10.10.10' # 设置服务器地址     sender = email_user + '@xxx.com.cn' # 发件人邮箱      # 创建一个带附件的实例     message = MIMEMultipart()          # 设置发件人、收件人     message['From'] = sender     message['To'] = ", ".join(receivers)     # 设置邮件主题     message['Subject'] = Header('查冻扣报备文件', 'utf-8')     # 邮件正文     message.attach(MIMEText('查冻扣报备文件已发送，请查看附件！', 'plain', 'utf-8'))      # 构造附件     xlsx = MIMEApplication(open(filepath,'rb').read())     xlsx['Content-Type'] = 'application/octet-stream'     filename = os.path.basename(filepath)     xlsx.add_header('Content-Disposition', 'attachment', filename=Header(filename, 'utf-8').encode())     message.attach(xlsx)      try:         smtpObj = smtplib.SMTP(mail_host, 1025)         smtpObj.login(email_user, email_pass)         smtpObj.sendmail(sender, receivers, message.as_string())         print("邮件发送成功，收件人：" + str(receivers) + "n 附件地址:" + str(filepath))     except smtplib.SMTPException as e:         print("邮件发送失败，收件人：" + str(receivers) + "n 附件地址:" + str(filepath))         print(e)

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